How to solve -6-[10+(-8-3)-1]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -6-[10+(-8-3)-1] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-6-[10+(-8-3)-1]$$

Evaluate

$-4$

Solution Steps

Subtract $8$ from $10$ to get $2$.

$$-6-\left(2-3-1\right)$$

Subtract $3$ from $2$ to get $-1$.

$$-6-\left(-1-1\right)$$

Subtract $1$ from $-1$ to get $-2$.

$$-6-\left(-2\right)$$

The opposite of $-2$ is $2$.

$$-6+2$$

Add $-6$ and $2$ to get $-4$.

$$-4$$

Show Solution

Factor

$-4$

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