How to solve - 6(2k - 2) >= 96

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 6(2k - 2) >= 96 | Equatix

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Question

$$-6(2k-2)\ge96$$

Solve for k

$k\leq -7$

Solution Steps

Divide both sides by $-6$. Since $-6$ is negative, the inequality direction is changed.

$$2k-2\leq \frac{96}{-6}$$

Divide $96$ by $-6$ to get $-16$.

$$2k-2\leq -16$$

Add $2$ to both sides.

$$2k\leq -16+2$$

Add $-16$ and $2$ to get $-14$.

$$2k\leq -14$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$k\leq \frac{-14}{2}$$

Divide $-14$ by $2$ to get $-7$.

$$k\leq -7$$

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