$$-6(d+2) < -9d+3(d-1)$$
$d\in \mathrm{R}$
$$-6d-12<-9d+3\left(d-1\right)$$
$$-6d-12<-9d+3d-3$$
$$-6d-12<-6d-3$$
$$-6d-12+6d<-3$$
$$-12<-3$$
$$d\in \mathrm{R}$$
Show Solution
Hide Solution