Solve -6(-2)+8-(2)+4(-3) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-6(-2)+8-(2)+4(-3)$$

Evaluate

$6$

Solution Steps

Multiply $-6$ and $-2$ to get $12$. Multiply $4$ and $-3$ to get $-12$.

$$12+8-2-12$$

Add $12$ and $8$ to get $20$.

$$20-2-12$$

Subtract $2$ from $20$ to get $18$.

$$18-12$$

Subtract $12$ from $18$ to get $6$.

$$6$$

Factor

$2\times 3$