How to solve - 6 + p/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 6 + p/2 | Equatix

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$$-6+\frac{p}{2}$$

$\frac{p}{2}-6$

To add or subtract expressions, expand them to make their denominators the same. Multiply $-6$ times $\frac{2}{2}$.

$$-\frac{6\times 2}{2}+\frac{p}{2}$$

Since $-\frac{6\times 2}{2}$ and $\frac{p}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{-6\times 2+p}{2}$$

Do the multiplications in $-6\times 2+p$.

$$\frac{-12+p}{2}$$

$\frac{p-12}{2}$