How to solve -6 imes2-5 imes-3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -6\times2-5\times-3 | Equatix

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3(r+2s)=2t-4

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Question

$$-6 \times 2-5 \times -3$$

Evaluate

$3$

Solution Steps

Multiply $-6$ and $2$ to get $-12$.

$$-12-5\left(-3\right)$$

Multiply $5$ and $-3$ to get $-15$.

$$-12-\left(-15\right)$$

The opposite of $-15$ is $15$.

$$-12+15$$

Add $-12$ and $15$ to get $3$.

$$3$$

Show Solution

Factor

$3$

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