$$-7 { x }^{ 2 } y+3xy+3$$
$y\left(3-14x\right)$
$$2\left(-7y\right)x^{2-1}+3yx^{1-1}$$
$$\left(-14y\right)x^{2-1}+3yx^{1-1}$$
$$\left(-14y\right)x^{1}+3yx^{1-1}$$
$$\left(-14y\right)x^{1}+3yx^{0}$$
$$\left(-14y\right)x+3yx^{0}$$
$$\left(-14y\right)x+3y\times 1$$
$$\left(-14y\right)x+3y$$
Show Solution
Hide Solution
$3xy-7yx^{2}+3$