Solve -7/4+0+-9/5+19/10+11/14 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-7/4+0+-9/5+19/10+11/14$$

Evaluate

$-\frac{121}{140}\approx -0.864285714$

Solution Steps

Fraction $\frac{-7}{4}$ can be rewritten as $-\frac{7}{4}$ by extracting the negative sign.

$$-\frac{7}{4}+0+\frac{-9}{5}+\frac{19}{10}+\frac{11}{14}$$

Add $-\frac{7}{4}$ and $0$ to get $-\frac{7}{4}$.

$$-\frac{7}{4}+\frac{-9}{5}+\frac{19}{10}+\frac{11}{14}$$

Fraction $\frac{-9}{5}$ can be rewritten as $-\frac{9}{5}$ by extracting the negative sign.

$$-\frac{7}{4}-\frac{9}{5}+\frac{19}{10}+\frac{11}{14}$$

Least common multiple of $4$ and $5$ is $20$. Convert $-\frac{7}{4}$ and $\frac{9}{5}$ to fractions with denominator $20$.

$$-\frac{35}{20}-\frac{36}{20}+\frac{19}{10}+\frac{11}{14}$$

Since $-\frac{35}{20}$ and $\frac{36}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-35-36}{20}+\frac{19}{10}+\frac{11}{14}$$

Subtract $36$ from $-35$ to get $-71$.

$$-\frac{71}{20}+\frac{19}{10}+\frac{11}{14}$$

Least common multiple of $20$ and $10$ is $20$. Convert $-\frac{71}{20}$ and $\frac{19}{10}$ to fractions with denominator $20$.

$$-\frac{71}{20}+\frac{38}{20}+\frac{11}{14}$$

Since $-\frac{71}{20}$ and $\frac{38}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{-71+38}{20}+\frac{11}{14}$$

Add $-71$ and $38$ to get $-33$.

$$-\frac{33}{20}+\frac{11}{14}$$

Least common multiple of $20$ and $14$ is $140$. Convert $-\frac{33}{20}$ and $\frac{11}{14}$ to fractions with denominator $140$.

$$-\frac{231}{140}+\frac{110}{140}$$

Since $-\frac{231}{140}$ and $\frac{110}{140}$ have the same denominator, add them by adding their numerators.

$$\frac{-231+110}{140}$$

Add $-231$ and $110$ to get $-121$.

$$-\frac{121}{140}$$

Factor

$-\frac{121}{140} = -0.8642857142857143$