1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -7/8+16 | Equatix

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Question

$$-7/8+16$$

$\frac{121}{8}=15.125$

Fraction $\frac{-7}{8}$ can be rewritten as $-\frac{7}{8}$ by extracting the negative sign.

$$-\frac{7}{8}+16$$

Convert $16$ to fraction $\frac{128}{8}$.

$$-\frac{7}{8}+\frac{128}{8}$$

Since $-\frac{7}{8}$ and $\frac{128}{8}$ have the same denominator, add them by adding their numerators.

$$\frac{-7+128}{8}$$

Add $-7$ and $128$ to get $121$.

$$\frac{121}{8}$$

$\frac{11 ^ {2}}{2 ^ {3}} = 15\frac{1}{8} = 15.125$