How to solve -7x-(3x+1) < 1x-6

Q: How to solve -7x-(3x+1) < 1x-6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -7x-(3x+1) < 1x-6 | Equatix

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Question

$$-7x-(3x+1) < 1x-6$$

Solve for x

$x>\frac{5}{11}$

Solution Steps

To find the opposite of $3x+1$, find the opposite of each term.

$$-7x-3x-1<1x-6$$

Combine $-7x$ and $-3x$ to get $-10x$.

$$-10x-1<1x-6$$

Subtract $1x$ from both sides.

$$-10x-1-x<-6$$

Combine $-10x$ and $-x$ to get $-11x$.

$$-11x-1<-6$$

Add $1$ to both sides.

$$-11x<-6+1$$

Add $-6$ and $1$ to get $-5$.

$$-11x<-5$$

Divide both sides by $-11$. Since $-11$ is negative, the inequality direction is changed.

$$x>\frac{-5}{-11}$$

Fraction $\frac{-5}{-11}$ can be simplified to $\frac{5}{11}$ by removing the negative sign from both the numerator and the denominator.

$$x>\frac{5}{11}$$

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