How to solve -8-[-2-(-12)+3]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -8-[-2-(-12)+3] | Equatix

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3(r+2s)=2t-4

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Question

$$-8-[-2-(-12)+3]$$

Evaluate

$-21$

Solution Steps

The opposite of $-12$ is $12$.

$$-8-\left(-2+12+3\right)$$

Add $-2$ and $12$ to get $10$.

$$-8-\left(10+3\right)$$

Add $10$ and $3$ to get $13$.

$$-8-13$$

Subtract $13$ from $-8$ to get $-21$.

$$-21$$

Show Solution

Factor

$-21$

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