How to solve - 8 + 6i = a + bi

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 8 + 6i = a + bi | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-8+6i=a+bi$$

Solve for a

$a=-8+6i-ib$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$a+bi=-8+6i$$

Subtract $bi$ from both sides.

$$a=-8+6i-bi$$

Multiply $-1$ and $i$ to get $-i$.

$$a=-8+6i-ib$$

Show Solution

Solve for b

$b=ia+\left(6+8i\right)$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$a+bi=-8+6i$$

Subtract $a$ from both sides.

$$bi=-8+6i-a$$

The equation is in standard form.

$$ib=-8+6i-a$$

Divide both sides by $i$.

$$\frac{ib}{i}=\frac{-8+6i-a}{i}$$

Dividing by $i$ undoes the multiplication by $i$.

$$b=\frac{-8+6i-a}{i}$$

Divide $-8+6i-a$ by $i$.

$$b=ia+\left(6+8i\right)$$

Show Solution

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