How to solve -8+(4-10)-(5-8)+3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -8+(4-10)-(5-8)+3 | Equatix

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Question

$$-8+(4-10)-(5-8)+3$$

Evaluate

$-8$

Solution Steps

Add $-8$ and $4$ to get $-4$.

$$-4-10-\left(5-8\right)+3$$

Subtract $10$ from $-4$ to get $-14$.

$$-14-\left(5-8\right)+3$$

Subtract $8$ from $5$ to get $-3$.

$$-14-\left(-3\right)+3$$

The opposite of $-3$ is $3$.

$$-14+3+3$$

Add $-14$ and $3$ to get $-11$.

$$-11+3$$

Add $-11$ and $3$ to get $-8$.

$$-8$$

Show Solution

Factor

$-8$

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