How to solve -80+6-3(-3)+4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -80+6-3(-3)+4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-80+6-3(-3)+4$$

Evaluate

$-61$

Solution Steps

Add $-80$ and $6$ to get $-74$.

$$-74-3\left(-3\right)+4$$

Multiply $3$ and $-3$ to get $-9$.

$$-74-\left(-9\right)+4$$

The opposite of $-9$ is $9$.

$$-74+9+4$$

Add $-74$ and $9$ to get $-65$.

$$-65+4$$

Add $-65$ and $4$ to get $-61$.

$$-61$$

Show Solution

Factor

$-61$

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