Solve -(9)^(3)\div(-9)^(2)+-(10)^(3)\div-10-(2)^(8)\div-(2)^(7)

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$- { 9 }^{ 3 } \div { -9 }^{ 2 } +- { 10 }^{ 3 } \div -10- { 2 }^{ 8 } \div - { 2 }^{ 7 }$$

Evaluate

$93$

Solution Steps

Calculate $9$ to the power of $3$ and get $729$.

$$\frac{-729}{\left(-9\right)^{2}}+\frac{-10^{3}}{-10}-\frac{2^{8}}{-2^{7}}$$

Calculate $-9$ to the power of $2$ and get $81$.

$$\frac{-729}{81}+\frac{-10^{3}}{-10}-\frac{2^{8}}{-2^{7}}$$

Divide $-729$ by $81$ to get $-9$.

$$-9+\frac{-10^{3}}{-10}-\frac{2^{8}}{-2^{7}}$$

Calculate $10$ to the power of $3$ and get $1000$.

$$-9+\frac{-1000}{-10}-\frac{2^{8}}{-2^{7}}$$

Divide $-1000$ by $-10$ to get $100$.

$$-9+100-\frac{2^{8}}{-2^{7}}$$

Add $-9$ and $100$ to get $91$.

$$91-\frac{2^{8}}{-2^{7}}$$

Calculate $2$ to the power of $8$ and get $256$.

$$91-\frac{256}{-2^{7}}$$

Calculate $2$ to the power of $7$ and get $128$.

$$91-\frac{256}{-128}$$

Divide $256$ by $-128$ to get $-2$.

$$91-\left(-2\right)$$

The opposite of $-2$ is $2$.

$$91+2$$

Add $91$ and $2$ to get $93$.

$$93$$

Show Solution

Factor

$3\times 31$