How to solve - 1/15 + 1 - 9/10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 1/15 + 1 - 9/10 | Equatix

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$$-\frac{1}{15}+1-\frac{9}{10}$$

$\frac{1}{30}\approx 0.033333333$

Convert $1$ to fraction $\frac{15}{15}$.

$$-\frac{1}{15}+\frac{15}{15}-\frac{9}{10}$$

Since $-\frac{1}{15}$ and $\frac{15}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{-1+15}{15}-\frac{9}{10}$$

Add $-1$ and $15$ to get $14$.

$$\frac{14}{15}-\frac{9}{10}$$

Least common multiple of $15$ and $10$ is $30$. Convert $\frac{14}{15}$ and $\frac{9}{10}$ to fractions with denominator $30$.

$$\frac{28}{30}-\frac{27}{30}$$

Since $\frac{28}{30}$ and $\frac{27}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{28-27}{30}$$

Subtract $27$ from $28$ to get $1$.

$$\frac{1}{30}$$

$\frac{1}{2 \cdot 3 \cdot 5} = 0.03333333333333333$