1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$- \frac { 1 } { 30 } = \frac { 1 } { 2 } + \frac { 3 } { 10 }$$

$\text{false}$

Least common multiple of $2$ and $10$ is $10$. Convert $\frac{1}{2}$ and $\frac{3}{10}$ to fractions with denominator $10$.

$$-\frac{1}{30}=\frac{5}{10}+\frac{3}{10}$$

Since $\frac{5}{10}$ and $\frac{3}{10}$ have the same denominator, add them by adding their numerators.

$$-\frac{1}{30}=\frac{5+3}{10}$$

Add $5$ and $3$ to get $8$.

$$-\frac{1}{30}=\frac{8}{10}$$

Reduce the fraction $\frac{8}{10}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{1}{30}=\frac{4}{5}$$

Least common multiple of $30$ and $5$ is $30$. Convert $-\frac{1}{30}$ and $\frac{4}{5}$ to fractions with denominator $30$.

$$-\frac{1}{30}=\frac{24}{30}$$

Compare $-\frac{1}{30}$ and $\frac{24}{30}$.

$$\text{false}$$