1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$[ - \frac { 1 } { 4 } ] \div \frac { 3 } { 8 } + [ - \frac { 1 } { 2 } ]$$

$-\frac{7}{6}\approx -1.166666667$

Divide $-\frac{1}{4}$ by $\frac{3}{8}$ by multiplying $-\frac{1}{4}$ by the reciprocal of $\frac{3}{8}$.

$$-\frac{1}{4}\times \frac{8}{3}-\frac{1}{2}$$

Multiply $-\frac{1}{4}$ times $\frac{8}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{-8}{4\times 3}-\frac{1}{2}$$

Do the multiplications in the fraction $\frac{-8}{4\times 3}$.

$$\frac{-8}{12}-\frac{1}{2}$$

Reduce the fraction $\frac{-8}{12}$ to lowest terms by extracting and canceling out $4$.

$$-\frac{2}{3}-\frac{1}{2}$$

Least common multiple of $3$ and $2$ is $6$. Convert $-\frac{2}{3}$ and $\frac{1}{2}$ to fractions with denominator $6$.

$$-\frac{4}{6}-\frac{3}{6}$$

Since $-\frac{4}{6}$ and $\frac{3}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-3}{6}$$

Subtract $3$ from $-4$ to get $-7$.

$$-\frac{7}{6}$$

$-\frac{7}{6} = -1\frac{1}{6} = -1.1666666666666667$