$$- \frac { 12 } { 58 } y ^ { 3 } z ^ { 2 } - \frac { 36 } { 29 } y z$$
$-\frac{6yz\left(zy^{2}+6\right)}{29}$
$$\frac{6\left(-y^{3}z^{2}-6yz\right)}{29}$$
$$yz\left(-y^{2}z-6\right)$$
$$\frac{6yz\left(-y^{2}z-6\right)}{29}$$
Show Solution
Hide Solution