How to solve -(2)/(3) imes4-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -(2)/(3)\times4-2 | Equatix

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$$- \frac{ 2 }{ 3 } \times 4-2$$

$-\frac{14}{3}\approx -4.666666667$

Express $-\frac{2}{3}\times 4$ as a single fraction.

$$\frac{-2\times 4}{3}-2$$

Multiply $-2$ and $4$ to get $-8$.

$$\frac{-8}{3}-2$$

Fraction $\frac{-8}{3}$ can be rewritten as $-\frac{8}{3}$ by extracting the negative sign.

$$-\frac{8}{3}-2$$

Convert $2$ to fraction $\frac{6}{3}$.

$$-\frac{8}{3}-\frac{6}{3}$$

Since $-\frac{8}{3}$ and $\frac{6}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-6}{3}$$

Subtract $6$ from $-8$ to get $-14$.

$$-\frac{14}{3}$$

$-\frac{14}{3} = -4\frac{2}{3} = -4.666666666666667$