$$- \frac { 2 } { 5 } \times ( \frac { 3 } { 10 } + 1 ) = ( - \frac { 2 } { 5 } \times \frac { 3 } { 10 } ) + ( - \frac { 2 } { 5 } \times \frac { 1 } { 15 }$$
$\text{false}$
$$-\frac{2}{5}\left(\frac{3}{10}+\frac{10}{10}\right)=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{2}{5}\times \frac{3+10}{10}=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{2}{5}\times \frac{13}{10}=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$\frac{-2\times 13}{5\times 10}=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$\frac{-26}{50}=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{13}{25}=-\frac{2}{5}\times \frac{3}{10}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{13}{25}=\frac{-2\times 3}{5\times 10}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{13}{25}=\frac{-6}{50}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{13}{25}=-\frac{3}{25}-\frac{2}{5}\times \frac{1}{15}$$
$$-\frac{13}{25}=-\frac{3}{25}+\frac{-2}{5\times 15}$$
$$-\frac{13}{25}=-\frac{3}{25}+\frac{-2}{75}$$
$$-\frac{13}{25}=-\frac{3}{25}-\frac{2}{75}$$
$$-\frac{13}{25}=-\frac{9}{75}-\frac{2}{75}$$
$$-\frac{13}{25}=\frac{-9-2}{75}$$
$$-\frac{13}{25}=-\frac{11}{75}$$
$$-\frac{39}{75}=-\frac{11}{75}$$
$$\text{false}$$
Show Solution
Hide Solution