Solve -(22)/(15)\div-(33)/(10) | Equatix

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Question

$$- \frac{ 22 }{ 15 } \div - \frac{ 33 }{ 10 }$$

$\frac{4}{9}\approx 0.444444444$

Divide $-\frac{22}{15}$ by $-\frac{33}{10}$ by multiplying $-\frac{22}{15}$ by the reciprocal of $-\frac{33}{10}$.

$$-\frac{22}{15}\left(-\frac{10}{33}\right)$$

Multiply $-\frac{22}{15}$ times $-\frac{10}{33}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{-22\left(-10\right)}{15\times 33}$$

Do the multiplications in the fraction $\frac{-22\left(-10\right)}{15\times 33}$.

$$\frac{220}{495}$$

Reduce the fraction $\frac{220}{495}$ to lowest terms by extracting and canceling out $55$.

$$\frac{4}{9}$$

$\frac{2 ^ {2}}{3 ^ {2}} = 0.4444444444444444$