$$- \frac{ 3 }{ 4 } \sqrt{ 17 } + \sqrt{ 3 } + \frac{ 6 }{ 8 } \sqrt{ 17 }$$
$\sqrt{3}\approx 1.732050808$
$$-\frac{3}{4}\sqrt{17}+\sqrt{3}+\frac{3}{4}\sqrt{17}$$
$$\sqrt{3}$$
Show Solution
Hide Solution
