Question

$$- \frac{ 4 }{ 3 } [ \frac{ 1 }{ 6 } \times (- \frac{ 7 }{ 4 } +(- \frac{ 3 }{ 8 } ))]$$

Answer

(24*8])/(3[1*17)

Solution


Remove parentheses.
-4/(3\(\frac{1}{6}(-\frac{7}{4}-\frac{3}{8})\))
Simplify  \(-\frac{7}{4}-\frac{3}{8}\)  to  \(-\frac{17}{8}\).
-4/(3\(\frac{1}{6}\times \frac{-17}{8}\))
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
-4/((3\(1\times -17\)))
Simplify negative sign.
-4/((-3\(1\times 17\)))
Move the negative sign to the left.
-4/(-(3\(1\times 17\)))
Move the negative sign to the left.
-(-4/((3\(1\times 17\))))
Invert and multiply.
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
Simplify  \(4\times 6\)  to  \(24\).
Remove parentheses.