How to solve - 5/3 - 3/2 + 1/6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve - 5/3 - 3/2 + 1/6 | Equatix

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$$-\frac{5}{3}-\frac{3}{2}+\frac{1}{6}$$

$-3$

Least common multiple of $3$ and $2$ is $6$. Convert $-\frac{5}{3}$ and $\frac{3}{2}$ to fractions with denominator $6$.

$$-\frac{10}{6}-\frac{9}{6}+\frac{1}{6}$$

Since $-\frac{10}{6}$ and $\frac{9}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-10-9}{6}+\frac{1}{6}$$

Subtract $9$ from $-10$ to get $-19$.

$$-\frac{19}{6}+\frac{1}{6}$$

Since $-\frac{19}{6}$ and $\frac{1}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{-19+1}{6}$$

Add $-19$ and $1$ to get $-18$.

$$\frac{-18}{6}$$

Divide $-18$ by $6$ to get $-3$.

$$-3$$

$-3$