$$-\frac{6}{13}-(\frac{-7}{15})$$
$\frac{1}{195}\approx 0.005128205$
$$-\frac{6}{13}-\left(-\frac{7}{15}\right)$$
$$-\frac{6}{13}+\frac{7}{15}$$
$$-\frac{90}{195}+\frac{91}{195}$$
$$\frac{-90+91}{195}$$
$$\frac{1}{195}$$
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$\frac{1}{3 \cdot 5 \cdot 13} = 0.005128205128205128$