$$- \frac { 9 } { 4 } x - \frac { 1 } { - 3 }$$
$-\frac{9x}{4}+\frac{1}{3}$
$$-\frac{9}{4}x-\left(-\frac{1}{3}\right)$$
$$-\frac{9}{4}x+\frac{1}{3}$$
Show Solution
Hide Solution
$\frac{4-27x}{12}$
$$\frac{-27x+4}{12}$$