$$-(b-z)-(-2b+z)-(-3b-z)$$
$z+4b$
$$-b-\left(-z\right)-\left(-2b+z\right)-\left(-3b-z\right)$$
$$-b+z-\left(-2b+z\right)-\left(-3b-z\right)$$
$$-b+z-\left(-2b\right)-z-\left(-3b-z\right)$$
$$-b+z+2b-z-\left(-3b-z\right)$$
$$b+z-z-\left(-3b-z\right)$$
$$b-\left(-3b-z\right)$$
$$b-\left(-3b\right)-\left(-z\right)$$
$$b+3b-\left(-z\right)$$
$$b+3b+z$$
$$4b+z$$
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