How to solve -(N-8)+7(1+6x)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -(N-8)+7(1+6x) | Equatix

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3(r+2s)=2t-4

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Question

$$-(N-8)+7(1+6x)$$

Evaluate

$42x-N+15$

Solution Steps

To find the opposite of $N-8$, find the opposite of each term.

$$-N-\left(-8\right)+7\left(1+6x\right)$$

The opposite of $-8$ is $8$.

$$-N+8+7\left(1+6x\right)$$

Use the distributive property to multiply $7$ by $1+6x$.

$$-N+8+7+42x$$

Add $8$ and $7$ to get $15$.

$$-N+15+42x$$

Show Solution

Expand

$42x-N+15$

Solution Steps

To find the opposite of $N-8$, find the opposite of each term.

$$-N-\left(-8\right)+7\left(1+6x\right)$$

The opposite of $-8$ is $8$.

$$-N+8+7\left(1+6x\right)$$

Use the distributive property to multiply $7$ by $1+6x$.

$$-N+8+7+42x$$

Add $8$ and $7$ to get $15$.

$$-N+15+42x$$

Show Solution

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Question

Evaluate

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Solution Steps