How to solve -(z+12)=5(2z-1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -(z+12)=5(2z-1) | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$-(z+12)=5(2z-1)$$

Solve for z

$z=-\frac{7}{11}\approx -0.636363636$

Steps for Solving Linear Equation

To find the opposite of $z+12$, find the opposite of each term.

$$-z-12=5\left(2z-1\right)$$

Use the distributive property to multiply $5$ by $2z-1$.

$$-z-12=10z-5$$

Subtract $10z$ from both sides.

$$-z-12-10z=-5$$

Combine $-z$ and $-10z$ to get $-11z$.

$$-11z-12=-5$$

Add $12$ to both sides.

$$-11z=-5+12$$

Add $-5$ and $12$ to get $7$.

$$-11z=7$$

Divide both sides by $-11$.

$$z=\frac{7}{-11}$$

Fraction $\frac{7}{-11}$ can be rewritten as $-\frac{7}{11}$ by extracting the negative sign.

$$z=-\frac{7}{11}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for z

Steps for Solving Linear Equation