How to solve -sqrt(3/2)+1/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -sqrt(3/2)+1/2 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$- \sqrt{ 3/2 } +1/2$$

$\frac{1-\sqrt{6}}{2}\approx -0.724744871$

Rewrite the square root of the division $\sqrt{\frac{3}{2}}$ as the division of square roots $\frac{\sqrt{3}}{\sqrt{2}}$.

$$-\frac{\sqrt{3}}{\sqrt{2}}+\frac{1}{2}$$

Rationalize the denominator of $\frac{\sqrt{3}}{\sqrt{2}}$ by multiplying numerator and denominator by $\sqrt{2}$.

$$-\frac{\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}+\frac{1}{2}$$

The square of $\sqrt{2}$ is $2$.

$$-\frac{\sqrt{3}\sqrt{2}}{2}+\frac{1}{2}$$

To multiply $\sqrt{3}$ and $\sqrt{2}$, multiply the numbers under the square root.

$$-\frac{\sqrt{6}}{2}+\frac{1}{2}$$

Since $\frac{\sqrt{6}}{2}$ and $\frac{1}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{\sqrt{6}+1}{2}$$

$\frac{1 - \sqrt{6}}{2} = -0.7247448713915889$