Solve MN=sqrt((-7-(-9))+(3-15)) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$MN= \sqrt{ (-7-(-9))+(3-15) }$$

Solve for M

$M=\frac{\sqrt{10}i}{N}$
$N\neq 0$

Steps for Solving Linear Equation

The opposite of $-9$ is $9$.

$$MN=\sqrt{-7+9+3-15}$$

Add $-7$ and $9$ to get $2$.

$$MN=\sqrt{2+3-15}$$

Add $2$ and $3$ to get $5$.

$$MN=\sqrt{5-15}$$

Subtract $15$ from $5$ to get $-10$.

$$MN=\sqrt{-10}$$

Factor $-10=10\left(-1\right)$. Rewrite the square root of the product $\sqrt{10\left(-1\right)}$ as the product of square roots $\sqrt{10}\sqrt{-1}$. By definition, the square root of $-1$ is $i$.

$$MN=\sqrt{10}i$$

The equation is in standard form.

$$NM=\sqrt{10}i$$

Divide both sides by $N$.

$$\frac{NM}{N}=\frac{\sqrt{10}i}{N}$$

Dividing by $N$ undoes the multiplication by $N$.

$$M=\frac{\sqrt{10}i}{N}$$

Solve for N

$N=\frac{\sqrt{10}i}{M}$
$M\neq 0$

Steps for Solving Linear Equation

The opposite of $-9$ is $9$.

$$MN=\sqrt{-7+9+3-15}$$

Add $-7$ and $9$ to get $2$.

$$MN=\sqrt{2+3-15}$$

Add $2$ and $3$ to get $5$.

$$MN=\sqrt{5-15}$$

Subtract $15$ from $5$ to get $-10$.

$$MN=\sqrt{-10}$$

Factor $-10=10\left(-1\right)$. Rewrite the square root of the product $\sqrt{10\left(-1\right)}$ as the product of square roots $\sqrt{10}\sqrt{-1}$. By definition, the square root of $-1$ is $i$.

$$MN=\sqrt{10}i$$

Divide both sides by $M$.

$$\frac{MN}{M}=\frac{\sqrt{10}i}{M}$$

Dividing by $M$ undoes the multiplication by $M$.

$$N=\frac{\sqrt{10}i}{M}$$