Question

$$\mu \alpha \sigma_{\bar{x}} \mu_{\bar{x}} =$$

Answer

$$IM*m^3*u*a^2*l*p*h*s*g*a_bar(x)*u_bar(x)$$

Solution


Regroup terms.
\[mmmuaalphsg\imath a_bar(x)u_bar(x)\]
Simplify.
\[{m}^{3}u{a}^{2}lphsg\imath a_bar(x)u_bar(x)\]
Regroup terms.
\[\imath {m}^{3}u{a}^{2}lphsga_bar(x)u_bar(x)\]