Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[n=0,05\times {10}^{8}\times 0,21,2\times {10}^{6}-0,04\times {10}^{7}\]
Simplify \(05\times {10}^{8}\times 0\) to \(0\).
\[n=0,0,21,2\times {10}^{6}-0,04\times {10}^{7}\]
Simplify \(04\times {10}^{7}\) to \(4\times {10}^{7}\).
\[n=0,0,21,2\times {10}^{6}-0,4\times {10}^{7}\]
Simplify \(2\times {10}^{6}-0\) to \(2\times {10}^{6}\).
\[n=0,0,21,2\times {10}^{6},4\times {10}^{7}\]
Therefore,
\(n=0,21,2\times {10}^{6},4\times {10}^{7}\)
n=0,21,2*10^6,4*10^7
