How to solve n+7<5n-8=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve n+7<5n-8= | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$n+7<5n-8=$$

$n>\frac{15}{4}$

Subtract $5n$ from both sides.

$$n+7-5n<-8$$

Combine $n$ and $-5n$ to get $-4n$.

$$-4n+7<-8$$

Subtract $7$ from both sides.

$$-4n<-8-7$$

Subtract $7$ from $-8$ to get $-15$.

$$-4n<-15$$

Divide both sides by $-4$. Since $-4$ is negative, the inequality direction is changed.

$$n>\frac{-15}{-4}$$

Fraction $\frac{-15}{-4}$ can be simplified to $\frac{15}{4}$ by removing the negative sign from both the numerator and the denominator.

$$n>\frac{15}{4}$$