Question

$$O { B }^{ 2 } = { 1 }^{ 2 } + { 2 }^{ 2 }$$

Solve for O

$O=\frac{5}{B^{2}}$
$B\neq 0$

Show Solution

Solve for B (complex solution)

$B=-\sqrt{5}O^{-\frac{1}{2}}$
$B=\sqrt{5}O^{-\frac{1}{2}}\text{, }O\neq 0$

Solve for B

$B=\sqrt{\frac{5}{O}}$
$B=-\sqrt{\frac{5}{O}}\text{, }O>0$