Question

$$og_{3}(2x+1)-\log_{3}x-3=2$$

Solve for g_3 (complex solution)

$\left\{\begin{matrix}g_{3}=\frac{\log_{3}\left(x\right)+5}{o\left(2x+1\right)}\text{, }&x\neq -\frac{1}{2}\text{ and }o\neq 0\text{ and }x\neq 0\\g_{3}\in \mathrm{C}\text{, }&o=0\text{ and }x=\frac{1}{243}\end{matrix}\right.$

Solve for o (complex solution)

$\left\{\begin{matrix}o=\frac{\log_{3}\left(x\right)+5}{g_{3}\left(2x+1\right)}\text{, }&x\neq -\frac{1}{2}\text{ and }g_{3}\neq 0\text{ and }x\neq 0\\o\in \mathrm{C}\text{, }&g_{3}=0\text{ and }x=\frac{1}{243}\end{matrix}\right.$

Solve for g_3

$\left\{\begin{matrix}g_{3}=\frac{\log_{3}\left(x\right)+5}{o\left(2x+1\right)}\text{, }&o\neq 0\text{ and }x>0\\g_{3}\in \mathrm{R}\text{, }&o=0\text{ and }x=\frac{1}{243}\end{matrix}\right.$

Solve for o

$\left\{\begin{matrix}o=\frac{\log_{3}\left(x\right)+5}{g_{3}\left(2x+1\right)}\text{, }&g_{3}\neq 0\text{ and }x>0\\o\in \mathrm{R}\text{, }&g_{3}=0\text{ and }x=\frac{1}{243}\end{matrix}\right.$