Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\operatorname { c o s e c } 2 A + \operatorname { c o s e c } 4 A = ( \cot A - C )$$

Answer

K=(NoCo*sec(2)*A+Co*sec(4)*A-Co*tA+Co)/4

Solution


Subtract \(CotA\) from both sides.
\[NoCo\sec{2}A+Co\sec{4}A-CotA=-Co+4K\]
Regroup terms.
\[NoCo\sec{2}A+Co\sec{4}A-CotA=4K-Co\]
Add \(Co\) to both sides.
\[NoCo\sec{2}A+Co\sec{4}A-CotA+Co=4K\]
Divide both sides by \(4\).
\[\frac{NoCo\sec{2}A+Co\sec{4}A-CotA+Co}{4}=K\]
Switch sides.
\[K=\frac{NoCo\sec{2}A+Co\sec{4}A-CotA+Co}{4}\]
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