Question

$$\overline{1\frac{1}{2}}=5th$$

Answer

$$o=(5*t*h)/(112*e^2*IM*v*r*l*n)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[ov{e}^{2}rl\imath n\times 112=5th\]
Regroup terms.
\[112{e}^{2}\imath ovrln=5th\]
Divide both sides by \(112\).
\[{e}^{2}\imath ovrln=\frac{5th}{112}\]
Divide both sides by \({e}^{2}\).
\[\imath ovrln=\frac{\frac{5th}{112}}{{e}^{2}}\]
Simplify  \(\frac{\frac{5th}{112}}{{e}^{2}}\)  to  \(\frac{5th}{112{e}^{2}}\).
\[\imath ovrln=\frac{5th}{112{e}^{2}}\]
Divide both sides by \(\imath \).
\[ovrln=\frac{\frac{5th}{112{e}^{2}}}{\imath }\]
Simplify  \(\frac{\frac{5th}{112{e}^{2}}}{\imath }\)  to  \(\frac{5th}{112{e}^{2}\imath }\).
\[ovrln=\frac{5th}{112{e}^{2}\imath }\]
Divide both sides by \(v\).
\[orln=\frac{\frac{5th}{112{e}^{2}\imath }}{v}\]
Simplify  \(\frac{\frac{5th}{112{e}^{2}\imath }}{v}\)  to  \(\frac{5th}{112{e}^{2}\imath v}\).
\[orln=\frac{5th}{112{e}^{2}\imath v}\]
Divide both sides by \(r\).
\[oln=\frac{\frac{5th}{112{e}^{2}\imath v}}{r}\]
Simplify  \(\frac{\frac{5th}{112{e}^{2}\imath v}}{r}\)  to  \(\frac{5th}{112{e}^{2}\imath vr}\).
\[oln=\frac{5th}{112{e}^{2}\imath vr}\]
Divide both sides by \(l\).
\[on=\frac{\frac{5th}{112{e}^{2}\imath vr}}{l}\]
Simplify  \(\frac{\frac{5th}{112{e}^{2}\imath vr}}{l}\)  to  \(\frac{5th}{112{e}^{2}\imath vrl}\).
\[on=\frac{5th}{112{e}^{2}\imath vrl}\]
Divide both sides by \(n\).
\[o=\frac{\frac{5th}{112{e}^{2}\imath vrl}}{n}\]
Simplify  \(\frac{\frac{5th}{112{e}^{2}\imath vrl}}{n}\)  to  \(\frac{5th}{112{e}^{2}\imath vrln}\).
\[o=\frac{5th}{112{e}^{2}\imath vrln}\]