Question

$$\overline{m+n}=\sqrt{m}\cdot\sqrt{n}$$

Answer

$$o=(sqrt(m*n)-n)/(e^2*IM*v*r*l*n*m)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[ov{e}^{2}rl\imath nm+n=\sqrt{m}\sqrt{n}\]
Regroup terms.
\[{e}^{2}\imath ovrlnm+n=\sqrt{m}\sqrt{n}\]
Regroup terms.
\[n+{e}^{2}\imath ovrlnm=\sqrt{m}\sqrt{n}\]
Subtract \(n\) from both sides.
\[{e}^{2}\imath ovrlnm=\sqrt{mn}-n\]
Divide both sides by \({e}^{2}\).
\[\imath ovrlnm=\frac{\sqrt{mn}-n}{{e}^{2}}\]
Divide both sides by \(\imath \).
\[ovrlnm=\frac{\frac{\sqrt{mn}-n}{{e}^{2}}}{\imath }\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}}}{\imath }\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath }\).
\[ovrlnm=\frac{\sqrt{mn}-n}{{e}^{2}\imath }\]
Divide both sides by \(v\).
\[orlnm=\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath }}{v}\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath }}{v}\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath v}\).
\[orlnm=\frac{\sqrt{mn}-n}{{e}^{2}\imath v}\]
Divide both sides by \(r\).
\[olnm=\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath v}}{r}\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath v}}{r}\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath vr}\).
\[olnm=\frac{\sqrt{mn}-n}{{e}^{2}\imath vr}\]
Divide both sides by \(l\).
\[onm=\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vr}}{l}\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vr}}{l}\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath vrl}\).
\[onm=\frac{\sqrt{mn}-n}{{e}^{2}\imath vrl}\]
Divide both sides by \(n\).
\[om=\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vrl}}{n}\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vrl}}{n}\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath vrln}\).
\[om=\frac{\sqrt{mn}-n}{{e}^{2}\imath vrln}\]
Divide both sides by \(m\).
\[o=\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vrln}}{m}\]
Simplify  \(\frac{\frac{\sqrt{mn}-n}{{e}^{2}\imath vrln}}{m}\)  to  \(\frac{\sqrt{mn}-n}{{e}^{2}\imath vrlnm}\).
\[o=\frac{\sqrt{mn}-n}{{e}^{2}\imath vrlnm}\]