Solve p=1.04q-7.03,p=-0.81+7.5 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$p=1.04q-7.03,p=-0.81+7.5$$

Solve for p, q

$p=6.69$
$q = \frac{343}{26} = 13\frac{5}{26} \approx 13.192307692$

Solution Steps

Consider the second equation. Add $-0.81$ and $7.5$ to get $6.69$.

$$p=6.69$$

Consider the first equation. Insert the known values of variables into the equation.

$$6.69=1.04q-7.03$$

Swap sides so that all variable terms are on the left hand side.

$$1.04q-7.03=6.69$$

Add $7.03$ to both sides.

$$1.04q=6.69+7.03$$

Add $6.69$ and $7.03$ to get $13.72$.

$$1.04q=13.72$$

Divide both sides by $1.04$.

$$q=\frac{13.72}{1.04}$$

Expand $\frac{13.72}{1.04}$ by multiplying both numerator and the denominator by $100$.

$$q=\frac{1372}{104}$$

Reduce the fraction $\frac{1372}{104}$ to lowest terms by extracting and canceling out $4$.

$$q=\frac{343}{26}$$

The system is now solved.

$$p=6.69$$ $$q=\frac{343}{26}$$