Question

$$P= \frac{ 5 }{ x } THEN { \left( { x }^{ 2 } - \frac{ 1 }{ { x }^{ 2 } } \right) }^{ 2 } =$$

Answer

$$P=(5*THEN(x^2-1/x^2)^2)/x$$

Solution


Did you want to graph this instead?
Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\[P=\frac{5{THEN({x}^{2}-\frac{1}{{x}^{2}})}^{2}}{x}\]