Solve P(k) = 5/(k(k + 1)) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$P(k)=\frac{5}{k(k+1)}$$

Solve for P

$P=\frac{5}{\left(k+1\right)k^{2}}$
$k\neq 0\text{ and }k\neq -1$

Steps for Solving Linear Equation

Multiply both sides of the equation by $k\left(k+1\right)$.

$$Pkk\left(k+1\right)=5$$

Multiply $k$ and $k$ to get $k^{2}$.

$$Pk^{2}\left(k+1\right)=5$$

Use the distributive property to multiply $Pk^{2}$ by $k+1$.

$$Pk^{3}+Pk^{2}=5$$

Combine all terms containing $P$.

$$\left(k^{3}+k^{2}\right)P=5$$

Divide both sides by $k^{3}+k^{2}$.

$$\frac{\left(k^{3}+k^{2}\right)P}{k^{3}+k^{2}}=\frac{5}{k^{3}+k^{2}}$$

Dividing by $k^{3}+k^{2}$ undoes the multiplication by $k^{3}+k^{2}$.

$$P=\frac{5}{k^{3}+k^{2}}$$

Divide $5$ by $k^{3}+k^{2}$.

$$P=\frac{5}{\left(k+1\right)k^{2}}$$