Question

$$p(x)=4 { x }^{ 3 } -6 { x }^{ 2 } +3x+14,p(0)$$

Answer

$$p=(4*x^3-6*x^2+3*x+14)/x,0$$

Solution


Simplify  \(p\times 0\)  to  \(0\).
\[px=4{x}^{3}-6{x}^{2}+3x+14,0\]
Break down the problem into these 2 equations.
\[px=4{x}^{3}-6{x}^{2}+3x+14\]
\[px=0\]
Solve the 1st equation: \(px=4{x}^{3}-6{x}^{2}+3x+14\).
\[p=\frac{4{x}^{3}-6{x}^{2}+3x+14}{x}\]
Solve the 2nd equation: \(px=0\).
\[p=0\]
Collect all solutions.
\[p=\frac{4{x}^{3}-6{x}^{2}+3x+14}{x},0\]