Solve P + (- 10) + (- 2) + (- 6) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$P+(-10)+(-2)+(-6)$$

Evaluate

$P-18$

Differentiate w.r.t. P

$1$

Steps Using Derivative Rule for Sum

Subtract $2$ from $-10$ to get $-12$.

$$\frac{\mathrm{d}}{\mathrm{d}P}(P-12-6)$$

Subtract $6$ from $-12$ to get $-18$.

$$\frac{\mathrm{d}}{\mathrm{d}P}(P-18)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$P^{1-1}$$

Subtract $1$ from $1$.

$$P^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$