How to solve (0-2+4-6+4-0)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (0-2+4-6+4-0) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(0-2+4-6+4-0)$$

Evaluate

$0$

Solution Steps

Subtract $2$ from $0$ to get $-2$.

$$-2+4-6+4-0$$

Add $-2$ and $4$ to get $2$.

$$2-6+4-0$$

Subtract $6$ from $2$ to get $-4$.

$$-4+4-0$$

Add $-4$ and $4$ to get $0$.

$$0-0$$

Subtracting $0$ from itself leaves $0$.

$$0$$

Show Solution

Factor

$0$

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Factor