Solve (0 + 2) - (6 - 2) + (3 + 0) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(0+2)-(6-2)+(3-0)$$

Evaluate

$1$

Solution Steps

Add $0$ and $2$ to get $2$.

$$2-\left(6-2\right)+3-0$$

Subtract $2$ from $6$ to get $4$.

$$2-4+3-0$$

Subtract $4$ from $2$ to get $-2$.

$$-2+3-0$$

Subtract $0$ from $3$ to get $3$.

$$-2+3$$

Add $-2$ and $3$ to get $1$.

$$1$$

Factor

$1$