How to solve (1/120+1/50)30/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1/120+1/50)30/8 | Equatix

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Question

$$(1/120+1/50)30/8$$

Evaluate

$\frac{17}{160}=0.10625$

Solution Steps

Least common multiple of $120$ and $50$ is $600$. Convert $\frac{1}{120}$ and $\frac{1}{50}$ to fractions with denominator $600$.

$$\frac{\left(\frac{5}{600}+\frac{12}{600}\right)\times 30}{8}$$

Since $\frac{5}{600}$ and $\frac{12}{600}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{5+12}{600}\times 30}{8}$$

Add $5$ and $12$ to get $17$.

$$\frac{\frac{17}{600}\times 30}{8}$$

Express $\frac{17}{600}\times 30$ as a single fraction.

$$\frac{\frac{17\times 30}{600}}{8}$$

Multiply $17$ and $30$ to get $510$.

$$\frac{\frac{510}{600}}{8}$$

Reduce the fraction $\frac{510}{600}$ to lowest terms by extracting and canceling out $30$.

$$\frac{\frac{17}{20}}{8}$$

Express $\frac{\frac{17}{20}}{8}$ as a single fraction.

$$\frac{17}{20\times 8}$$

Multiply $20$ and $8$ to get $160$.

$$\frac{17}{160}$$

Show Solution

Factor

$\frac{17}{2 ^ {5} \cdot 5} = 0.10625$