How to solve (1/120+1/500)30/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1/120+1/500)30/8 | Equatix

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Question

$$(1/120+1/500)30/8$$

Evaluate

$\frac{31}{800}=0.03875$

Solution Steps

Least common multiple of $120$ and $500$ is $3000$. Convert $\frac{1}{120}$ and $\frac{1}{500}$ to fractions with denominator $3000$.

$$\frac{\left(\frac{25}{3000}+\frac{6}{3000}\right)\times 30}{8}$$

Since $\frac{25}{3000}$ and $\frac{6}{3000}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{25+6}{3000}\times 30}{8}$$

Add $25$ and $6$ to get $31$.

$$\frac{\frac{31}{3000}\times 30}{8}$$

Express $\frac{31}{3000}\times 30$ as a single fraction.

$$\frac{\frac{31\times 30}{3000}}{8}$$

Multiply $31$ and $30$ to get $930$.

$$\frac{\frac{930}{3000}}{8}$$

Reduce the fraction $\frac{930}{3000}$ to lowest terms by extracting and canceling out $30$.

$$\frac{\frac{31}{100}}{8}$$

Express $\frac{\frac{31}{100}}{8}$ as a single fraction.

$$\frac{31}{100\times 8}$$

Multiply $100$ and $8$ to get $800$.

$$\frac{31}{800}$$

Show Solution

Factor

$\frac{31}{2 ^ {5} \cdot 5 ^ {2}} = 0.03875$