How to solve (1-3x)(1+3x)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1-3x)(1+3x) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(1-3x)(1+3x)$$

Evaluate

$1-9x^{2}$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$.

$$1^{2}-\left(3x\right)^{2}$$

Calculate $1$ to the power of $2$ and get $1$.

$$1-\left(3x\right)^{2}$$

Expand $\left(3x\right)^{2}$.

$$1-3^{2}x^{2}$$

Calculate $3$ to the power of $2$ and get $9$.

$$1-9x^{2}$$

Show Solution

Expand

$1-9x^{2}$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$.

$$1^{2}-\left(3x\right)^{2}$$

Calculate $1$ to the power of $2$ and get $1$.

$$1-\left(3x\right)^{2}$$

Expand $\left(3x\right)^{2}$.

$$1-3^{2}x^{2}$$

Calculate $3$ to the power of $2$ and get $9$.

$$1-9x^{2}$$

Show Solution

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Question

Evaluate

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Solution Steps